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2x(4x-3)=2x-12
We move all terms to the left:
2x(4x-3)-(2x-12)=0
We multiply parentheses
8x^2-6x-(2x-12)=0
We get rid of parentheses
8x^2-6x-2x+12=0
We add all the numbers together, and all the variables
8x^2-8x+12=0
a = 8; b = -8; c = +12;
Δ = b2-4ac
Δ = -82-4·8·12
Δ = -320
Delta is less than zero, so there is no solution for the equation
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