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2x(4x+8)=88
We move all terms to the left:
2x(4x+8)-(88)=0
We multiply parentheses
8x^2+16x-88=0
a = 8; b = 16; c = -88;
Δ = b2-4ac
Δ = 162-4·8·(-88)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32\sqrt{3}}{2*8}=\frac{-16-32\sqrt{3}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32\sqrt{3}}{2*8}=\frac{-16+32\sqrt{3}}{16} $
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