-2(y-5y)+3=-3(5y-y)+6+19y

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Solution for -2(y-5y)+3=-3(5y-y)+6+19y equation: 



-2(y-5y)+3=-3(5y-y)+6+19y

We move all terms to the left:

-2(y-5y)+3-(-3(5y-y)+6+19y)=0

We add all the numbers together, and all the variables

-2(-4y)-(-3(+4y)+6+19y)+3=0

We multiply parentheses

8y-(-3(+4y)+6+19y)+3=0



We calculate terms in parentheses: -(-3(+4y)+6+19y), so:

-3(+4y)+6+19y

determiningTheFunctionDomain
-3(+4y)+19y+6

We add all the numbers together, and all the variables

19y-3(+4y)+6

We multiply parentheses

19y-12y+6

We add all the numbers together, and all the variables

7y+6

Back to the equation:

-(7y+6)



We get rid of parentheses

8y-7y-6+3=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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