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2x(4+x)=960
We move all terms to the left:
2x(4+x)-(960)=0
We add all the numbers together, and all the variables
2x(x+4)-960=0
We multiply parentheses
2x^2+8x-960=0
a = 2; b = 8; c = -960;
Δ = b2-4ac
Δ = 82-4·2·(-960)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*2}=\frac{-96}{4} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*2}=\frac{80}{4} =20 $
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