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X+18=1/2X+36
We move all terms to the left:
X+18-(1/2X+36)=0
Domain of the equation: 2X+36)!=0We get rid of parentheses
X∈R
X-1/2X-36+18=0
We multiply all the terms by the denominator
X*2X-36*2X+18*2X-1=0
Wy multiply elements
2X^2-72X+36X-1=0
We add all the numbers together, and all the variables
2X^2-36X-1=0
a = 2; b = -36; c = -1;
Δ = b2-4ac
Δ = -362-4·2·(-1)
Δ = 1304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1304}=\sqrt{4*326}=\sqrt{4}*\sqrt{326}=2\sqrt{326}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{326}}{2*2}=\frac{36-2\sqrt{326}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{326}}{2*2}=\frac{36+2\sqrt{326}}{4} $
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