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2x(4+5x)+3-4x-1=-4x
We move all terms to the left:
2x(4+5x)+3-4x-1-(-4x)=0
We add all the numbers together, and all the variables
2x(5x+4)-4x-(-4x)+3-1=0
We add all the numbers together, and all the variables
-4x+2x(5x+4)-(-4x)+2=0
We multiply parentheses
10x^2-4x+8x-(-4x)+2=0
We get rid of parentheses
10x^2-4x+8x+4x+2=0
We add all the numbers together, and all the variables
10x^2+8x+2=0
a = 10; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·10·2
Δ = -16
Delta is less than zero, so there is no solution for the equation
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