2x(3x-12)=180

Solution for 2x(3x-12)=180 equation:

2x(3x-12)=180

We move all terms to the left:

2x(3x-12)-(180)=0

We multiply parentheses

6x^2-24x-180=0

a = 6; b = -24; c = -180;
Δ = b2-4ac
Δ = -242-4·6·(-180)
Δ = 4896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4896}=\sqrt{144*34}=\sqrt{144}*\sqrt{34}=12\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{34}}{2*6}=\frac{24-12\sqrt{34}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{34}}{2*6}=\frac{24+12\sqrt{34}}{12}
$