7(2x+3)-3(5x-2)=5(3x-4)

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Solution for 7(2x+3)-3(5x-2)=5(3x-4) equation: 



7(2x+3)-3(5x-2)=5(3x-4)

We move all terms to the left:

7(2x+3)-3(5x-2)-(5(3x-4))=0

We multiply parentheses

14x-15x-(5(3x-4))+21+6=0



We calculate terms in parentheses: -(5(3x-4)), so:

5(3x-4)

We multiply parentheses

15x-20

Back to the equation:

-(15x-20)



We add all the numbers together, and all the variables

-1x-(15x-20)+27=0

We get rid of parentheses

-1x-15x+20+27=0

We add all the numbers together, and all the variables

-16x+47=0

We move all terms containing x to the left, all other terms to the right

-16x=-47

x=-47/-16

x=2+15/16

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