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2x(3x+5)=2x-3
We move all terms to the left:
2x(3x+5)-(2x-3)=0
We multiply parentheses
6x^2+10x-(2x-3)=0
We get rid of parentheses
6x^2+10x-2x+3=0
We add all the numbers together, and all the variables
6x^2+8x+3=0
a = 6; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·6·3
Δ = -8
Delta is less than zero, so there is no solution for the equation
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