(3x-5)+(2x-3)+(2x+7)+(15-2x)=32

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Solution for (3x-5)+(2x-3)+(2x+7)+(15-2x)=32 equation: 



(3x-5)+(2x-3)+(2x+7)+(15-2x)=32

We move all terms to the left:

(3x-5)+(2x-3)+(2x+7)+(15-2x)-(32)=0

We add all the numbers together, and all the variables

(3x-5)+(2x-3)+(2x+7)+(-2x+15)-32=0

We get rid of parentheses

3x+2x+2x-2x-5-3+7+15-32=0

We add all the numbers together, and all the variables

5x-18=0

We move all terms containing x to the left, all other terms to the right

5x=18

x=18/5

x=3+3/5

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