2x(2x-4)+10=(4x-3)(x+5)

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Solution for 2x(2x-4)+10=(4x-3)(x+5) equation: 



2x(2x-4)+10=(4x-3)(x+5)

We move all terms to the left:

2x(2x-4)+10-((4x-3)(x+5))=0

We multiply parentheses

4x^2-8x-((4x-3)(x+5))+10=0

We multiply parentheses ..

4x^2-((+4x^2+20x-3x-15))-8x+10=0



We calculate terms in parentheses: -((+4x^2+20x-3x-15)), so:

(+4x^2+20x-3x-15)

We get rid of parentheses

4x^2+20x-3x-15

We add all the numbers together, and all the variables

4x^2+17x-15

Back to the equation:

-(4x^2+17x-15)



We add all the numbers together, and all the variables

4x^2-8x-(4x^2+17x-15)+10=0

We get rid of parentheses

4x^2-4x^2-8x-17x+15+10=0

We add all the numbers together, and all the variables

-25x+25=0

We move all terms containing x to the left, all other terms to the right

-25x=-25

x=-25/-25

x=1

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