14(t-4)+3t=6(3t+2)-8

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Solution for 14(t-4)+3t=6(3t+2)-8 equation: 



14(t-4)+3t=6(3t+2)-8

We move all terms to the left:

14(t-4)+3t-(6(3t+2)-8)=0

We add all the numbers together, and all the variables

3t+14(t-4)-(6(3t+2)-8)=0

We multiply parentheses

3t+14t-(6(3t+2)-8)-56=0



We calculate terms in parentheses: -(6(3t+2)-8), so:

6(3t+2)-8

We multiply parentheses

18t+12-8

We add all the numbers together, and all the variables

18t+4

Back to the equation:

-(18t+4)



We add all the numbers together, and all the variables

17t-(18t+4)-56=0

We get rid of parentheses

17t-18t-4-56=0

We add all the numbers together, and all the variables

-1t-60=0

We move all terms containing t to the left, all other terms to the right

-t=60

t=60/-1

t=-60

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