4c+2=10(c-16)

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Solution for 4c+2=10(c-16) equation: 



4c+2=10(c-16)

We move all terms to the left:

4c+2-(10(c-16))=0



We calculate terms in parentheses: -(10(c-16)), so:

10(c-16)

We multiply parentheses

10c-160

Back to the equation:

-(10c-160)



We get rid of parentheses

4c-10c+160+2=0

We add all the numbers together, and all the variables

-6c+162=0

We move all terms containing c to the left, all other terms to the right

-6c=-162

c=-162/-6

c=+27

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