2x(2+3x)=11(8x)

Solution for 2x(2+3x)=11(8x) equation:

2x(2+3x)=11(8x)

We move all terms to the left:

2x(2+3x)-(11(8x))=0

determiningTheFunctionDomain
2x(2+3x)-118x=0

We add all the numbers together, and all the variables

2x(3x+2)-118x=0

We add all the numbers together, and all the variables

-118x+2x(3x+2)=0

We multiply parentheses

6x^2-118x+4x=0

We add all the numbers together, and all the variables

6x^2-114x=0

a = 6; b = -114; c = 0;
Δ = b2-4ac
Δ = -1142-4·6·0
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-114)-114}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-114)+114}{2*6}=\frac{228}{12}
=19
$