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2x(2+3x)=2x(2+3x)
We move all terms to the left:
2x(2+3x)-(2x(2+3x))=0
We add all the numbers together, and all the variables
2x(3x+2)-(2x(3x+2))=0
We multiply parentheses
6x^2+4x-(2x(3x+2))=0
We calculate terms in parentheses: -(2x(3x+2)), so:We get rid of parentheses
2x(3x+2)
We multiply parentheses
6x^2+4x
Back to the equation:
-(6x^2+4x)
6x^2-6x^2+4x-4x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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