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2x(12+x)/2=x
We move all terms to the left:
2x(12+x)/2-(x)=0
We add all the numbers together, and all the variables
2x(x+12)/2-x=0
We add all the numbers together, and all the variables
-1x+2x(x+12)/2=0
We multiply all the terms by the denominator
-1x*2+2x(x+12)=0
We multiply parentheses
2x^2-1x*2+24x=0
Wy multiply elements
2x^2-2x+24x=0
We add all the numbers together, and all the variables
2x^2+22x=0
a = 2; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·2·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*2}=\frac{0}{4} =0 $
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