3(u+2)+2u=7(u+1)+9

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Solution for 3(u+2)+2u=7(u+1)+9 equation: 



3(u+2)+2u=7(u+1)+9

We move all terms to the left:

3(u+2)+2u-(7(u+1)+9)=0

We add all the numbers together, and all the variables

2u+3(u+2)-(7(u+1)+9)=0

We multiply parentheses

2u+3u-(7(u+1)+9)+6=0



We calculate terms in parentheses: -(7(u+1)+9), so:

7(u+1)+9

We multiply parentheses

7u+7+9

We add all the numbers together, and all the variables

7u+16

Back to the equation:

-(7u+16)



We add all the numbers together, and all the variables

5u-(7u+16)+6=0

We get rid of parentheses

5u-7u-16+6=0

We add all the numbers together, and all the variables

-2u-10=0

We move all terms containing u to the left, all other terms to the right

-2u=10

u=10/-2

u=-5

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