2w2+24w+72=0

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Solution for 2w2+24w+72=0 equation: 



2w^2+24w+72=0

a = 2; b = 24; c = +72;
Δ = b2-4ac
Δ = 242-4·2·72
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-24}{4}=-6$

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