2v-4+2(4v+4)=-4(v+2)

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Solution for 2v-4+2(4v+4)=-4(v+2) equation: 



2v-4+2(4v+4)=-4(v+2)

We move all terms to the left:

2v-4+2(4v+4)-(-4(v+2))=0

We multiply parentheses

2v+8v-(-4(v+2))+8-4=0



We calculate terms in parentheses: -(-4(v+2)), so:

-4(v+2)

We multiply parentheses

-4v-8

Back to the equation:

-(-4v-8)



We add all the numbers together, and all the variables

10v-(-4v-8)+4=0

We get rid of parentheses

10v+4v+8+4=0

We add all the numbers together, and all the variables

14v+12=0

We move all terms containing v to the left, all other terms to the right

14v=-12

v=-12/14

v=-6/7

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