2(x+8)=-2(8x-4)+6x

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Solution for 2(x+8)=-2(8x-4)+6x equation: 



2(x+8)=-2(8x-4)+6x

We move all terms to the left:

2(x+8)-(-2(8x-4)+6x)=0

We multiply parentheses

2x-(-2(8x-4)+6x)+16=0



We calculate terms in parentheses: -(-2(8x-4)+6x), so:

-2(8x-4)+6x

We add all the numbers together, and all the variables

6x-2(8x-4)

We multiply parentheses

6x-16x+8

We add all the numbers together, and all the variables

-10x+8

Back to the equation:

-(-10x+8)



We get rid of parentheses

2x+10x-8+16=0

We add all the numbers together, and all the variables

12x+8=0

We move all terms containing x to the left, all other terms to the right

12x=-8

x=-8/12

x=-2/3

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