2v-2+2(4v+1)=5(v+1)

Solution for 2v-2+2(4v+1)=5(v+1) equation:

2v-2+2(4v+1)=5(v+1)

We move all terms to the left:

2v-2+2(4v+1)-(5(v+1))=0

We multiply parentheses

2v+8v-(5(v+1))+2-2=0


We calculate terms in parentheses: -(5(v+1)), so:

5(v+1)

We multiply parentheses

5v+5

Back to the equation:

-(5v+5)


We add all the numbers together, and all the variables

10v-(5v+5)=0

We get rid of parentheses

10v-5v-5=0

We add all the numbers together, and all the variables

5v-5=0

We move all terms containing v to the left, all other terms to the right

5v=5

v=5/5

v=1