2u-32=3(u+6)

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Solution for 2u-32=3(u+6) equation: 



2u-32=3(u+6)

We move all terms to the left:

2u-32-(3(u+6))=0



We calculate terms in parentheses: -(3(u+6)), so:

3(u+6)

We multiply parentheses

3u+18

Back to the equation:

-(3u+18)



We get rid of parentheses

2u-3u-18-32=0

We add all the numbers together, and all the variables

-1u-50=0

We move all terms containing u to the left, all other terms to the right

-u=50

u=50/-1

u=-50

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