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43x=15-1/3x
We move all terms to the left:
43x-(15-1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
43x-(-1/3x+15)=0
We get rid of parentheses
43x+1/3x-15=0
We multiply all the terms by the denominator
43x*3x-15*3x+1=0
Wy multiply elements
129x^2-45x+1=0
a = 129; b = -45; c = +1;
Δ = b2-4ac
Δ = -452-4·129·1
Δ = 1509
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1509}}{2*129}=\frac{45-\sqrt{1509}}{258} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1509}}{2*129}=\frac{45+\sqrt{1509}}{258} $
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