2t-6(1+2t)=2t+9(5t+12)

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Solution for 2t-6(1+2t)=2t+9(5t+12) equation: 



2t-6(1+2t)=2t+9(5t+12)

We move all terms to the left:

2t-6(1+2t)-(2t+9(5t+12))=0

We add all the numbers together, and all the variables

2t-6(2t+1)-(2t+9(5t+12))=0

We multiply parentheses

2t-12t-(2t+9(5t+12))-6=0



We calculate terms in parentheses: -(2t+9(5t+12)), so:

2t+9(5t+12)

We multiply parentheses

2t+45t+108

We add all the numbers together, and all the variables

47t+108

Back to the equation:

-(47t+108)



We add all the numbers together, and all the variables

-10t-(47t+108)-6=0

We get rid of parentheses

-10t-47t-108-6=0

We add all the numbers together, and all the variables

-57t-114=0

We move all terms containing t to the left, all other terms to the right

-57t=114

t=114/-57

t=-2

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