10(2y+2)-y=2(8y-y)

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Solution for 10(2y+2)-y=2(8y-y) equation: 



10(2y+2)-y=2(8y-y)

We move all terms to the left:

10(2y+2)-y-(2(8y-y))=0

We add all the numbers together, and all the variables

10(2y+2)-y-(2(+7y))=0

We add all the numbers together, and all the variables

-1y+10(2y+2)-(2(+7y))=0

We multiply parentheses

-1y+20y-(2(+7y))+20=0



We calculate terms in parentheses: -(2(+7y)), so:

2(+7y)

We multiply parentheses

14y

Back to the equation:

-(14y)



We add all the numbers together, and all the variables

5y+20=0

We move all terms containing y to the left, all other terms to the right

5y=-20

y=-20/5

y=-4

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