2t-2=3(t+2)=

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Solution for 2t-2=3(t+2)= equation: 



2t-2=3(t+2)=

We move all terms to the left:

2t-2-(3(t+2))=0



We calculate terms in parentheses: -(3(t+2)), so:

3(t+2)

We multiply parentheses

3t+6

Back to the equation:

-(3t+6)



We get rid of parentheses

2t-3t-6-2=0

We add all the numbers together, and all the variables

-1t-8=0

We move all terms containing t to the left, all other terms to the right

-t=8

t=8/-1

t=-8

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