6(x-5)-10=3(4x-2)-4

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Solution for 6(x-5)-10=3(4x-2)-4 equation:



6(x-5)-10=3(4x-2)-4
We move all terms to the left:
6(x-5)-10-(3(4x-2)-4)=0
We multiply parentheses
6x-(3(4x-2)-4)-30-10=0
We calculate terms in parentheses: -(3(4x-2)-4), so:
3(4x-2)-4
We multiply parentheses
12x-6-4
We add all the numbers together, and all the variables
12x-10
Back to the equation:
-(12x-10)
We add all the numbers together, and all the variables
6x-(12x-10)-40=0
We get rid of parentheses
6x-12x+10-40=0
We add all the numbers together, and all the variables
-6x-30=0
We move all terms containing x to the left, all other terms to the right
-6x=30
x=30/-6
x=-5

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