2t+3/5=7

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Solution for 2t+3/5=7 equation: 



2t+3/5=7

We move all terms to the left:

2t+3/5-(7)=0

determiningTheFunctionDomain
2t-7+3/5=0

We multiply all the terms by the denominator


2t*5+3-7*5=0

We add all the numbers together, and all the variables

2t*5-32=0

Wy multiply elements

10t-32=0

We move all terms containing t to the left, all other terms to the right

10t=32

t=32/10

t=3+1/5

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