(3x-1)*(-x-5)=0

Solution for (3x-1)*(-x-5)=0 equation:

(3x-1)(-x-5)=0

We add all the numbers together, and all the variables

(3x-1)(-1x-5)=0

We multiply parentheses ..

(-3x^2-15x+x+5)=0

We get rid of parentheses

-3x^2-15x+x+5=0

We add all the numbers together, and all the variables

-3x^2-14x+5=0

a = -3; b = -14; c = +5;
Δ = b2-4ac
Δ = -142-4·(-3)·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-16}{2*-3}=\frac{-2}{-6}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+16}{2*-3}=\frac{30}{-6}
=-5
$