2r+2(r+4)=212

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Solution for 2r+2(r+4)=212 equation: 



2r+2(r+4)=212

We move all terms to the left:

2r+2(r+4)-(212)=0

We multiply parentheses

2r+2r+8-212=0

We add all the numbers together, and all the variables

4r-204=0

We move all terms containing r to the left, all other terms to the right

4r=204

r=204/4

r=51

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