2(x-8)+10=4-(x-2)

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Solution for 2(x-8)+10=4-(x-2) equation: 



2(x-8)+10=4-(x-2)

We move all terms to the left:

2(x-8)+10-(4-(x-2))=0

We multiply parentheses

2x-(4-(x-2))-16+10=0



We calculate terms in parentheses: -(4-(x-2)), so:

4-(x-2)

determiningTheFunctionDomain
-(x-2)+4

We get rid of parentheses

-x+2+4

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We add all the numbers together, and all the variables

2x-(-1x+6)-6=0

We get rid of parentheses

2x+1x-6-6=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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