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2p+1/3(6p-9)=2(p+1)
We move all terms to the left:
2p+1/3(6p-9)-(2(p+1))=0
Domain of the equation: 3(6p-9)!=0We multiply all the terms by the denominator
p∈R
2p*3(6p-9)-((2(p+1)))*3(6p-9)+1=0
We calculate terms in parentheses: -((2(p+1)))*3(6p-9), so:Wy multiply elements
(2(p+1)))*3(6p-9
6p^2(6-((2(p+1)))*3(6p-9)+1=0
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