2p(p+3)-3p(2p=1)

Solution for 2p(p+3)-3p(2p=1) equation:

2p(p+3)-3p(2p=1)

We move all terms to the left:

2p(p+3)-3p(2p-(1))=0

We multiply parentheses

2p^2-6p^2+6p+3p=0

We add all the numbers together, and all the variables

-4p^2+9p=0

a = -4; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-4)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-4}=\frac{-18}{-8}
=2+1/4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-4}=\frac{0}{-8}
=0
$