4a-7=3(a+1)+12+4

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Solution for 4a-7=3(a+1)+12+4 equation: 



4a-7=3(a+1)+12+4

We move all terms to the left:

4a-7-(3(a+1)+12+4)=0



We calculate terms in parentheses: -(3(a+1)+12+4), so:

3(a+1)+12+4

We add all the numbers together, and all the variables

3(a+1)+16

We multiply parentheses

3a+3+16

We add all the numbers together, and all the variables

3a+19

Back to the equation:

-(3a+19)



We get rid of parentheses

4a-3a-19-7=0

We add all the numbers together, and all the variables

a-26=0

We move all terms containing a to the left, all other terms to the right

a=26

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