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2n^2-180=0
a = 2; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·2·(-180)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*2}=\frac{0-12\sqrt{10}}{4} =-\frac{12\sqrt{10}}{4} =-3\sqrt{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*2}=\frac{0+12\sqrt{10}}{4} =\frac{12\sqrt{10}}{4} =3\sqrt{10} $
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