8v+4-2(-3v-5)=2(v-2)

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Solution for 8v+4-2(-3v-5)=2(v-2) equation: 



8v+4-2(-3v-5)=2(v-2)

We move all terms to the left:

8v+4-2(-3v-5)-(2(v-2))=0

We multiply parentheses

8v+6v-(2(v-2))+10+4=0



We calculate terms in parentheses: -(2(v-2)), so:

2(v-2)

We multiply parentheses

2v-4

Back to the equation:

-(2v-4)



We add all the numbers together, and all the variables

14v-(2v-4)+14=0

We get rid of parentheses

14v-2v+4+14=0

We add all the numbers together, and all the variables

12v+18=0

We move all terms containing v to the left, all other terms to the right

12v=-18

v=-18/12

v=-1+1/2

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