2n2+7=-4n+5

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Solution for 2n2+7=-4n+5 equation: 



2n^2+7=-4n+5

We move all terms to the left:

2n^2+7-(-4n+5)=0

We get rid of parentheses

2n^2+4n-5+7=0

We add all the numbers together, and all the variables

2n^2+4n+2=0

a = 2; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-4}{4}=-1$

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