8(y+2)-3(y-4)=6(y-7)

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Solution for 8(y+2)-3(y-4)=6(y-7) equation: 



8(y+2)-3(y-4)=6(y-7)

We move all terms to the left:

8(y+2)-3(y-4)-(6(y-7))=0

We multiply parentheses

8y-3y-(6(y-7))+16+12=0



We calculate terms in parentheses: -(6(y-7)), so:

6(y-7)

We multiply parentheses

6y-42

Back to the equation:

-(6y-42)



We add all the numbers together, and all the variables

5y-(6y-42)+28=0

We get rid of parentheses

5y-6y+42+28=0

We add all the numbers together, and all the variables

-1y+70=0

We move all terms containing y to the left, all other terms to the right

-y=-70

y=-70/-1

y=+70

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