2n-1=-3+5(n-2)

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Solution for 2n-1=-3+5(n-2) equation: 



2n-1=-3+5(n-2)

We move all terms to the left:

2n-1-(-3+5(n-2))=0



We calculate terms in parentheses: -(-3+5(n-2)), so:

-3+5(n-2)

determiningTheFunctionDomain
5(n-2)-3

We multiply parentheses

5n-10-3

We add all the numbers together, and all the variables

5n-13

Back to the equation:

-(5n-13)



We get rid of parentheses

2n-5n+13-1=0

We add all the numbers together, and all the variables

-3n+12=0

We move all terms containing n to the left, all other terms to the right

-3n=-12

n=-12/-3

n=+4

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