11+3/7y=41

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Solution for 11+3/7y=41 equation: 



11+3/7y=41

We move all terms to the left:

11+3/7y-(41)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



We add all the numbers together, and all the variables

3/7y-30=0

We multiply all the terms by the denominator


-30*7y+3=0

Wy multiply elements

-210y+3=0

We move all terms containing y to the left, all other terms to the right

-210y=-3

y=-3/-210

y=1/70

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