(2x-4)(2x+1)=150

Solution for (2x-4)(2x+1)=150 equation:

(2x-4)(2x+1)=150

We move all terms to the left:

(2x-4)(2x+1)-(150)=0

We multiply parentheses ..

(+4x^2+2x-8x-4)-150=0

We get rid of parentheses

4x^2+2x-8x-4-150=0

We add all the numbers together, and all the variables

4x^2-6x-154=0

a = 4; b = -6; c = -154;
Δ = b2-4ac
Δ = -62-4·4·(-154)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-50}{2*4}=\frac{-44}{8}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+50}{2*4}=\frac{56}{8}
=7
$