2n-1=(10n-5)/5

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Solution for 2n-1=(10n-5)/5 equation:



2n-1=(10n-5)/5
We move all terms to the left:
2n-1-((10n-5)/5)=0
We multiply all the terms by the denominator
2n*5)-((10n-5)-1*5)=0
We add all the numbers together, and all the variables
2n*5)-((10n-5)=0
Wy multiply elements
10n^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{20}=0$

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