5x+4x-48=80-7x

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Solution for 5x+4x-48=80-7x equation: 



5x+4x-48=80-7x

We move all terms to the left:

5x+4x-48-(80-7x)=0

We add all the numbers together, and all the variables

5x+4x-(-7x+80)-48=0

We add all the numbers together, and all the variables

9x-(-7x+80)-48=0

We get rid of parentheses

9x+7x-80-48=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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