2n+4(7-n)=2(4n+42)

Solution for 2n+4(7-n)=2(4n+42) equation:

2n+4(7-n)=2(4n+42)

We move all terms to the left:

2n+4(7-n)-(2(4n+42))=0

We add all the numbers together, and all the variables

2n+4(-1n+7)-(2(4n+42))=0

We multiply parentheses

2n-4n-(2(4n+42))+28=0


We calculate terms in parentheses: -(2(4n+42)), so:

2(4n+42)

We multiply parentheses

8n+84

Back to the equation:

-(8n+84)


We add all the numbers together, and all the variables

-2n-(8n+84)+28=0

We get rid of parentheses

-2n-8n-84+28=0

We add all the numbers together, and all the variables

-10n-56=0

We move all terms containing n to the left, all other terms to the right

-10n=56

n=56/-10

n=-5+3/5