2n(-1)=n(2)

Solution for 2n(-1)=n(2) equation:

2n(-1)=n(2)

We move all terms to the left:

2n(-1)-(n(2))=0

determiningTheFunctionDomain
2n(-1)-n2=0

We add all the numbers together, and all the variables

-1n^2+2n(-1)=0

We multiply parentheses

-1n^2-2n=0

a = -1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-1}=\frac{0}{-2}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-1}=\frac{4}{-2}
=-2
$