18(x+3)=2(9x-1)+56

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Solution for 18(x+3)=2(9x-1)+56 equation: 



18(x+3)=2(9x-1)+56

We move all terms to the left:

18(x+3)-(2(9x-1)+56)=0

We multiply parentheses

18x-(2(9x-1)+56)+54=0



We calculate terms in parentheses: -(2(9x-1)+56), so:

2(9x-1)+56

We multiply parentheses

18x-2+56

We add all the numbers together, and all the variables

18x+54

Back to the equation:

-(18x+54)



We get rid of parentheses

18x-18x-54+54=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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