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2m=+5(m-6)=3m+14
We move all terms to the left:
2m-(+5(m-6))=0
We calculate terms in parentheses: -(+5(m-6)), so:We get rid of parentheses
+5(m-6)
determiningTheFunctionDomain 5(m-6)
We multiply parentheses
5m-30
Back to the equation:
-(5m-30)
2m-5m+30=0
We add all the numbers together, and all the variables
-3m+30=0
We move all terms containing m to the left, all other terms to the right
-3m=-30
m=-30/-3
m=+10
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