(2x+16)(2x+24)=768

Solution for (2x+16)(2x+24)=768 equation:

(2x+16)(2x+24)=768

We move all terms to the left:

(2x+16)(2x+24)-(768)=0

We multiply parentheses ..

(+4x^2+48x+32x+384)-768=0

We get rid of parentheses

4x^2+48x+32x+384-768=0

We add all the numbers together, and all the variables

4x^2+80x-384=0

a = 4; b = 80; c = -384;
Δ = b2-4ac
Δ = 802-4·4·(-384)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-112}{2*4}=\frac{-192}{8}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+112}{2*4}=\frac{32}{8}
=4
$