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3x+4=5x^2
We move all terms to the left:
3x+4-(5x^2)=0
determiningTheFunctionDomain -5x^2+3x+4=0
a = -5; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-5)·4
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*-5}=\frac{-3-\sqrt{89}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*-5}=\frac{-3+\sqrt{89}}{-10} $
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