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2m^2+17m+15=0
a = 2; b = 17; c = +15;
Δ = b2-4ac
Δ = 172-4·2·15
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*2}=\frac{-30}{4} =-7+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*2}=\frac{-4}{4} =-1 $
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